Splitting a list into two lists in scala -

i have list containing like:

val lines: list[string] = list("bla blub -- id_1", "sdkfjdf -- id_2", "blubber blab -- id_1", "foo -- id_3", "ieriuer -- id_2", "bar -- id_3")

so list contains identifier exists twice (id_x) , string belongs 1 of identifiers.

i want split 1 list 2 lists each contains unique set of id_s belonging strings, this:

l1("bla blub -- id_1", "sdkfjdf -- id_2", "foo -- id_3")  l2("blubber blab -- id_1", "ieriuer -- id_2", "bar -- id_3")

how in functional way?

best regards, sven

lines.groupby(_.split(" -- ")(1)).tolist.map(_._2).transpose

that's rough , ready way it; in reality if want more data it'll better parse items case class, la:

case class item(id: string, text: string) val items = {   line <- lines   array(text, id) = line.split(" -- ") } yield item(id, text)

then same above, except groupby(_.id), , conveniently sortby(_.id) well.

You