python - Numpy: array of indices based on array shape? -

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say have simple array:

a = np.zeros([3,3]) >>> [ 0 0 0 , 0 0 0 , 0 0 0 ]

is there utility function give me array same dimensions contains "coordinates" of each point on a? so,

ia = np.indexer(a) >>> [ (0,0) (0,1) (0,2), (1,0) (1,1) (1,2), (2,0) (2,1) (2,2) ]

? want vectorize operation using np.ndenumerate, easier if output of ndenumerate in matrix form.

class glwidget(qtopengl.qglwidget):   target_array = none    ...    def paintgl(self):     glclear(gl_color_buffer_bit | gl_depth_buffer_bit)     self.render()    def render(self):     if self.target_array none:       return      starting_abs_point = -(np.array(self.target_array.shape)-1)/(2*np.max(self.target_array.shape))     gltranslate(*starting_abs_point)     last_rel_coords= np.zeros(3)      idx, value in np.ndenumerate(self.target_array): # vectorization target!       rel_coords = np.array(idx)/np.max(self.target_array.shape)       step = rel_coords-last_rel_coords       last_rel_coords = rel_coords        gltranslate(*step)       glutwirecube(value/( np.max(self.target_array)*np.max(self.target_array.shape) ))      gltranslate(*-(starting_abs_point+last_rel_coords))

goal (it looks terrible because can't lighting , stuff going yet, it's learning exercise): enter image description here


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