matlab - Deleting rows with specific rules -

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i got 20*3 cell array , need delete rows contains "137", "2" , "n:t"

origin data:

't'             ''          ''             'np(*)'         ''          ''             [       137]    ''          ''             [         2]    ''          ''             'are'           'and'       'np(fcc_a1#1)' ''              ''          '1:t'          [      1200]    [0.7052]    ''             [1.2051e+03]    [0.7076]    ''             'are'           'and'       'np(fcc_a1#3)' ''              ''          '2:t'          [      1200]    [0.0673]    ''             [1.2051e+03]    [0.0671]    ''             'are'           'and'       'np(m23c6)'    ''              ''          '3:t'          [      1200]    [0.2275]    ''             [1.2051e+03]    [0.2253]    ''             [       137]    ''          ''             [         2]    ''          ''

and want like

't'             ''          ''             'np(*)'         ''          ''                   'are'           'and'       'np(fcc_a1#1)'        [      1200]    [0.7052]    ''             [1.2051e+03]    [0.7076]    ''             'are'           'and'       'np(fcc_a1#3)'      [      1200]    [0.0673]    ''             [1.2051e+03]    [0.0671]    ''             'are'           'and'       'np(m23c6)'    [      1200]    [0.2275]    ''             [1.2051e+03]    [0.2253]    ''

i've tried regexp , strcmp , don't work well. plus cell array hard deal with. can help?

thank in advance.

if can somehow read original data cells strings or empty arrays (not numeric values), can strcmp , regexprep:

% variable 'data' 2d-cell array of strings or empty arrays  datarep = regexprep(data,'^\d+:t','2'); % replace 'n:t' '2' convenience remove1 = strcmp('2',datarep); % takes care of '2' , 'n:t' remove2 = strcmp('137',datarep); % takes care of '137' rows_keep = find(~sum(remove1|remove2,2)); % rows kept solution = data(rows_keep,:)

for example, data 

'aa'     'bb'       'cc'   'dd'     'dd'       '2'    '137'    'dd'       'dd'   'dd'     'dd'       '11:t' '1:t'    '1:137'    'dd'   'dd'     ''             []

the result in variable solution is

'aa'    'bb'    'cc' 'dd'    ''        []

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